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On top of a hill, a rocket is launched from a distance 80 feet above a lake. The rocket will fall into the lake after its engine burns out. The rocket's height, h, in feet above the surface of the lake, is given by the equation, h = -16t 2 + 64t + 80, where t is time in seconds. The maximum height of the rocket is
a0 feet.

Respuesta :

edwardosmith00
Are you trying to find the maximum height? The time it will be to reach the maximum height? I'm pretty confused at what you need help with right now

Answer:

Maximum height is 144 feet.

Step-by-step explanation:

A quadratic equation y =[tex]ax^2+bx+c=0[/tex] gives maximum value when x =[tex]\frac{-b}{2a}[/tex]

after finding the value of x we plug value of x in original equation in order to find the maximum value (minimum value in case of a >0)

on comparing given quadratic equation which is variable 't' ,we get a =-16 and  b =64

t =[tex]\frac{-64}{2(-16)}[/tex]

plugging this value of t =2 in  original equation in order to get maximum value of h

so h = [tex]\-16(2)^2+16(2)+80[/tex]

which gives h =144 feet

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