Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and the other is quadratic–without graphing the system of equations.

Respuesta :

Isolate one variable in the system of equations. Use substitution to create a one-variable equation. Then, set the quadratic equation equal to zero and find the discriminant. If the discriminant is negative, then there are no real number solutions. If the discriminant is zero, then there is one real number solution. If the discriminant is positive, then there are two real number solutions.

There are two real solution can be find out comparing the discriminant of the quadratic equation with zero.

Linear equation- Linear equation is one degree equation which means the highest power of the variable is always one. Example,

[tex]ax+by+c=0[/tex]

hear a, b, and c are constant and x and y are variables.

Quadratic equation-Quadratic equation is two degree equation which means the highest power of the variables is always two. Example,

[tex]ax^2+by+c=0[/tex]

If linear and quadratic equation is given in problem, solve them simultaneously and then take the discriminant of the resulting quadratic.

For quadratic equation written above, the discriminant is,

[tex]b^2-4ac[/tex]

By solving the above equation we can get three solution,

  1. If the value of above equation is less then zero, there are no real solution.
  2. If the value is equal to zero, there unique and repeated solution.
  3. if the value is greater than zero, there are two real solution.

For more about the quadratic equation, follow the link below-

https://brainly.com/question/6168075