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Bart found 20 quadrilaterals in his classroom. He made a Venn diagram using the properties of the quadrilaterals, comparing those with four equal side lengths (E) and those with four right angles (R).

Given that a randomly chosen quadrilateral has four right angles, what is the probability that the quadrilateral also has four equal side lengths? Express your answer in percent form, rounded to the nearest whole percent.

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PLEASE REALLY NEED HELP IM STRUGGLING Bart found 20 quadrilaterals in his classroom He made a Venn diagram using the properties of the quadrilaterals comparing class=

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frika

At Venn diagram there are 4 parts (20 pieces):

1. Colored only in blue - quadrilaterals with four equal side lengths (3 pieces);

2. Colored only in orange - quadrilaterals with four right angles (6 pieces);

3. Colored in both blue and orange - quadrilaterals with four right angles and with four equal side lengths (2 pieces);

4. Colored in white - quadrilaterals withoutprevious two properties (9 pieces).

Consider events:

A - a randomly chosen quadrilateral has four right angles;

B - a randomly chosen quadrilateral has four equal side lengths;

Use formula [tex] Pr(B|A)=\dfrac{Pr(A\cap B)}{Pr A} [/tex] to find the probability that a randomly selected quadrilateral with 4 right angles also has four equal side lengths:

[tex] Pr(A\cap B)=\dfrac{2}{20},\\Pr(A)=\dfrac{8}{20},\\Pr(B|A)=\dfrac{\frac{2}{20}}{\frac{8}{20}} =\dfrac{2}{8}=\dfrac{1}{4} =0.25 [/tex]

Answer: Pr=0.25

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By using the information in the Venn diagram we will see that given that a randomly chosen quadrilateral has four right angles, the probability that the quadrilateral also has four equal side lengths is 33%.

How to interpret a Venn diagram?

In the Venn diagram, we can see that we have 9 elements, 6 of these belong to the set R, 3 of them belong to the set E, and 2 belong to both sets.

Now we want to find the probability that, if a figure has four right angles (belongs to R) it also has 4 equal side lengths (belongs to E).

So, given that an element belongs to R (6 elements there). What is the probability that it also belongs to E?

2 out of these 6 elements belong to E, so the probability will be:

P = 2/6 = 1/3 = 0.33

To get this in percent form, we need to multiply it by 100%, we will get:

0.33*100% = 33%

If you want to learn more about probability, you can read:

https://brainly.com/question/251701

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