Respuesta :
Sample space is 36C4
Now, we want to know all of the combinations that have 1 digit in it.
So, we can have one here:
1XXX
X1XX
XX1X
XXX1
But we have 10 different digits to choose from. So, we need to introduce the combination term, nCr, where n is a list of all digits and r is how many we want.
Since we only want one, we will need 10C1 for the number of digits. But we need to choose three lowercases, so it becomes 10C1 × 26C3
Since it's a probability question, we need to divide that by our sample space, 36C4, and our percentage becomes 44%
Now, we want to know all of the combinations that have 1 digit in it.
So, we can have one here:
1XXX
X1XX
XX1X
XXX1
But we have 10 different digits to choose from. So, we need to introduce the combination term, nCr, where n is a list of all digits and r is how many we want.
Since we only want one, we will need 10C1 for the number of digits. But we need to choose three lowercases, so it becomes 10C1 × 26C3
Since it's a probability question, we need to divide that by our sample space, 36C4, and our percentage becomes 44%
Using the permutation formula, it is found that the approximate probability that exactly one of the four characters will be a number is of 44%.
What is a probability?
- A probability is given by the number of desired outcomes divided by the number of total outcomes.
In this problem, the order is important, as a different order means a different password, hence the permutation formula is used.
What is the permutation formula?
The number of possible permutations of x elements from a set of n elements is given by:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
In this problem, the total outcomes are given by 4 characters from a set of 36(26 lower-case letters and 10 digits), hence:
[tex]T = P_{36,4} = \frac{36!}{32!} = 1413720[/tex]
For the desired outcomes, we have:
- One number from a set of 10.
- Three letters from a set of 26.
- 4 possible arrangements(N-L-L-L, L-N-L-L, L-L-N-L, L-L-L-N), hence:
[tex]D = 4P_{10,1}P_{26,3} = 4\frac{10!}{9!}\frac{26!}{23!} = 624000[/tex]
Hence, the probability is of:
[tex]p = \frac{D}{T} = \frac{624000}{1413720} = 0.4414[/tex]
Hence of approximately 44%.
You can learn more about the permutation formula at https://brainly.com/question/25925367