Respuesta :
We are given the chemical reaction and the amount of reactant used for the process. We use these data together to obtain what is asked. We do as as follows:
0.882 mol H2O2 ( 1 mol O2 / 2 mol H2O2 ) = 0.441 mol O2 produced
Hope this answers the question.
0.882 mol H2O2 ( 1 mol O2 / 2 mol H2O2 ) = 0.441 mol O2 produced
Hope this answers the question.
Answer : The moles of oxygen gas will be, 0.441 mole
Explanation : Given,
Moles of [tex]H_2O_2[/tex] = 0.882 mole
The given balanced chemical reaction is,
[tex]2H_2O_2(l)\rightarrow 2H_2O(l)+O_2(g)[/tex]
From the balanced reaction we conclude that
As, 2 moles of [tex]H_2O_2[/tex] react to give 1 mole of [tex]O_2[/tex]
So, 0.882 moles of [tex]H_2O_2[/tex] react to give [tex]\frac{0.882}{2}=0.441[/tex] moles of [tex]O_2[/tex]
Therefore, the moles of oxygen gas will be, 0.441 mole
