Respuesta :
How can you solve it if you don't know the equations? :P Just kidding...
n+d=22, so we can say that d=22-n
5n+10d=120, and using d found above in this equation gives you:
5n+10(22-n)=120
5n+220-10n=120
-5n=-100
n=20, and since d=22-n, d=2
So there are two dimes and twenty nickels...
check...
20(5)+2(10)=100+20=120 cents which is $1.20
n+d=22, 20+2=22, 22=22
n+d=22, so we can say that d=22-n
5n+10d=120, and using d found above in this equation gives you:
5n+10(22-n)=120
5n+220-10n=120
-5n=-100
n=20, and since d=22-n, d=2
So there are two dimes and twenty nickels...
check...
20(5)+2(10)=100+20=120 cents which is $1.20
n+d=22, 20+2=22, 22=22
You have a pile of 22 coins that includes nickels and dimes
Let n= nickels and d= dimes
total coins= nickels and dimes
n+d=22
The total value of the coins is $1.20
d=1.20-n
You would solve by system of equations.
n+d=22
d=1.20-n
I suggest using process of substitution
Let n= nickels and d= dimes
total coins= nickels and dimes
n+d=22
The total value of the coins is $1.20
d=1.20-n
You would solve by system of equations.
n+d=22
d=1.20-n
I suggest using process of substitution