In the standardization of the Na2S2O3 solution, if you did not titrate the liberated iodine immediately, how would this likely affect the value of the molarity you calculate?

The titration should be done fastly because if not titrated immediatly the liberated I2 will go out of the system.So it will not react with the Na2S2O3.then the value we are getting for the Na2S2O3 is not the actuall value.The malority will smaller than the actual value.

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pstnonsonjoku pstnonsonjoku · Answer 2 · 2022-04-14T13:31:16+02:00

Iodine is capable of escaping from the system hence if the iodine is ot titrated immediately and some of it escapes, the molarity of iodine obtained will be lower than the actual value.

What is molarity?

The term molarity has to do with the amount of substance present. We have to note that iodine is capable of escaping from the system if it is not titrated immediately.

As such, if the iodine is ot titrated immediately and some of it escapes, the molarity of iodine obtained will be lower than the actual value.

Learn more about molarity: https://brainly.com/question/11256472