A spring, having an unstretched length of 2ft, has one end attached to the 10lb ball. determine the angle ? of the spring if the ball has a speed of 6 ft/s tangent to the horizontal circular path.

Respuesta :

The angle theta of the spring is 31 degrees. To solve for this, show the equation which is equal to the 10lb ball. With this, the unknown will be the angle. Then transpose/transfer the terms in order to isolate the variable for the angle. First solve for s, then solve for angle theta. You will come up with s = .5849 ft and angle theta = 31.2629 or 31 degrees. Hope this helps.