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Given that the average bond energies for c-h and c-br bonds are 413 and 276 kj/mol, respectively, the heat of atomization of bromoform (chbr3 is __________ kj/mol.

Respuesta :

Erudite1
The heat of atomization of CHBr3 is 1241.
C-H =413, C-Br3 =276*3 = 828
828 + 413 = 1241.

Answer:

Heat of atomization of CHBr3 = 1241 kJ/mol

Explanation:

Enthalpy of atomization is the enthalpy change that takes place when a molecule breaks down into its constituent atoms. In the case of CHBr3, the atomization reaction is:

CHBr3 → C + H + 3Br

In CHBr3, there is 1 C-H bond and 3 C-Br bonds, the heat of atomization is:

ΔH(a) = 413 + 3(276) = 1241 kJ/mol

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