Respuesta :
Answer:
Factorization of [tex]4x^2 + 36x + 72[/tex] is:
4(x+3)(x+6)
factors are: 4, x+3 and x+6
Step-by-step explanation:
we are given a expression:
[tex]4x^2 + 36x + 72[/tex]
We have to factorize this expression
[tex]4x^2 + 36x + 72=4(x^2+9x+18)[/tex]
Now, we factorize [tex](x^2+9x+18)[/tex]
[tex]x^2+9x+18=x^2+6x+3x+18\\\\=x(x+6)+3(x+6)\\\\=(x+3)(x+6)[/tex]
Hence, factorization of [tex]4x^2 + 36x + 72[/tex] is:
4(x+3)(x+6)
factors are: 4, x+3 and x+6
