How many, and what type of, solutions does 6x^2 - 2X + 7 = 0 have?

1 rational solution
2 no real solutions
2 rational solutions
2 irrational solutions

Respuesta :

yo need to use discriminant

for ax²+bx+c=0
the discriminat is b²-4ac

if the discriminant is
1. less than 0, then 0 real solutions
2. equal to 0, then 1 real solutions
3. if more than 0, then 2 real solutions

given

6x²-2x+7=0
a=6
b=-2
c=7
(-2)²-4(6)(7)
4-168
we can see this is less than 0
no real solutions

According to the discriminant of the quadratic equation, it is found that 6x^2 - 2X + 7 = 0 has 2 no real solutions.

What is the discriminant of a quadratic equation and how does it influence the solutions?

A quadratic equation is modeled by:

[tex]y = ax^2 + bx + c[/tex]

The discriminant is:

[tex]\Delta = b^2 - 4ac[/tex]

The solutions are as follows:

  • If [tex]\mathbf{\Delta > 0}[/tex], and it is a perfect square, it has 2 rational solutions.
  • If [tex]\mathbf{\Delta > 0}[/tex], and it is not a perfect square, it has 2 irrational solutions.
  • If [tex]\mathbf{\Delta = 0}[/tex], it has 1 rational solutions.
  • If [tex]\mathbf{\Delta < 0}[/tex], it has 2 complex solutions.

In this problem, the equation is:

[tex]6x^2 - 2x + 7 = 0[/tex]

Hence the coefficients are a = 6, b = -2, c = 7 and the discriminant is given by:

[tex]\Delta = (-2)^2 - 4(6)(7) = -164[/tex]

Negative discriminant, hence the correct option is 2 no real solutions.

More can be learned about quadratic equations at https://brainly.com/question/19776811