Respuesta :

[tex]\bf 9x^2+12x+4=0\\\ \begin{array}{lcclll} 9x^2&+12x&+4&=y\\ \uparrow &\uparrow &\uparrow \\ a&b&c \end{array}\qquad \begin{cases} discriminant\to b^2-4ac\\\\ \textit{if negative}\\ \textit{no solutions}\\ ----------\\ \textit{if positive}\\ \textit{two real solutions}\\ ----------\\ \textit{if 0}\\ \textit{one solution} \end{cases} [/tex]