Answer: The volume of 1.2 moles of oxygen gas ([tex]O_2[/tex]) at standard temperature and pressure (STP) is 26.9 Liters
Explanation:
Using ideal gas equation:
PV = nRT
[tex]V=\frac{nRT}{P}[/tex]
At standard conditions of temperature and pressure:
P= pressure = 1 atm
T = temperature = 273 K
V= volume = ?
Given: n = no of moles = 1.2
R= gas constant =0.0821 Latm\molK
Putting in the values we get:
[tex]V=\frac{1.2\times 0.0821Latm/Kmol\times 273}{1atm}=26.9L[/tex]
The volume of 1.2 moles of oxygen gas ([tex]O_2[/tex]) at standard temperature and pressure (STP) is 26.9 Liters
