Answer:
Option 1 is correct.
Step-by-step explanation:
We have different functions
we need to tell which one of them will have y-intercept
So, to find y-intercept we will put x=0
So, in first function put x=0 we get:
[tex]f(0)=log(0+1)-1[/tex]
[tex]\Rightarrow f(0)=log(1)-1[/tex]
[tex]\Rightarrow f(0)=-1[/tex]
Hence, the first function has y-intercept.
In all the last three functions:
When we put x=0 in f(x)=log x+1
We will get log(0) which is not defined
And x=0 in f(x)=log(x-1)+1
log(-1) which is also not defined.
And x=0 in f(x)=log(x-1)-1
Again not defined.
