he equation $y=-16t^2+22t+45$ describes the height (in feet) of a ball thrown upwards at $22$ feet per second from $45$ feet above the ground. Find the time (in seconds) when the ball will hit the ground. Express your answer as a common fraction.

Respuesta :

the ball hits the ground when y = 0:-
-16t^2 + 22t + 45 = 0
we need to solve this for t

t = 2 1/2 seconds