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A new company is hiring employees rapidly. every day, the number of employees doubles in size. if it takes 48 days for the company to be at full capacity, how many days would it take for the company to be at half capacity?

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taskmasters
base from the problem the doubling size of the company is one day. and it takes 48 days for the company to to be at full capacity. since the doubling rate is one day, so meaning a day before the company was full, the company is half of its capacity. so the answer is 47 days

It is stated in the question that the number of employees doubles every day. This means that the current day's capacity is the same as the day before.

It would take the company 47 days to be at half capacity.  This can be written in a mathematical form as follows:

  • [tex]\text{Current day capacity = Previous day capacity}[/tex] × [tex]2[/tex] [tex]......................... (1)[/tex]

We can suppose that the current day capacity (CDC), which in this case is the 48th day, is 100 employees. That is to say;

[tex]\text{CDC = 48th-day capacity}\\\text{CDC = 100}[/tex]

When we plug this into equation (1) and solve for previous day capacity, we get:

[tex]\text{100 = Previous day capacity (PDC)}[/tex] × [tex]2[/tex]

[tex]\text{PDC} = \frac{100}{2}\\PDC = 50[/tex]

Because 50 is half of 100 and the previous day was the 47th, the corporation would have to work for 47 days to reach half capacity.

For more information related to the question, refer to the link:

https://brainly.com/question/16653973

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