A)
Earlier, The length of the angelfish = [tex]1 \frac{1}{2}[/tex] inches
Now, the length of angelfish = [tex]2 \frac{1}{3}[/tex] inches
We have to determine the grown length of angelfish
= [tex]2 \frac{1}{3}[/tex] - [tex]1 \frac{1}{2}[/tex]
= [tex]\frac{7}{3}- \frac{3}{2}[/tex]
LCM of '2' and '3' is '6',
= [tex]\frac{14-9}{6}[/tex]
= [tex]\frac{5}{6}[/tex] inch
Therefore, the angelfish has grown by [tex]\frac{5}{6}[/tex] inch.
B)
We have to determine the increased length of angelfish in feet.
Since [tex]1 inch = \frac{1}{12}[/tex] foot
So, [tex]\frac{5}{6} inch = \frac{5}{6} \times \frac{1}{12} = \frac{5}{72}[/tex]
= 0.069 foot.
