Answer:
[tex](M^2+n^2)(M-n)(M+n)[/tex]
Step-by-step explanation:
This is a difference of squares polynomial of the form [tex]a^2-b^2=(a+b)(a-b)[/tex]. Since [tex]M^4[/tex] and [tex]n^4[/tex] are both perfect squares then take the square root of each so a=[tex]M^2[/tex] and b=[tex]n^2[/tex].
[tex](M^2+n^2)(M^2-n^2)[/tex]
We have another difference of squares and repeat the process.
[tex](M^2+n^2)(M-n)(M+n)[/tex]
Notice that a sum of squares is not factorable.
