Respuesta :
Answer:-564.4996 kJ is the change in enthalpy when 250 g of water vapor condenses at 100°C.
Explanation:
[tex]H_2O(l)\rightarrow H_2O(g),\Delta H_v=40.67 kJ/mol[/tex]
[tex][tex]H_2O(g)\rightarrow H_2O(l),\Delta H_c=-40.67 kJ/mol[/tex]
Moles of water = [tex]\frac{250 g}{18 g/mol}=13.88 mol[/tex]
Heat of condensation of 1 mol of water = [tex]\Delta H_v=-40.67 kJ/mol[/tex]
Heat change when 250 grams of water condenses at 100° C:
[tex]-40.67 kJ/mol\times 13.88 mol=-564.4996 kJ[/tex]
-564.4996 kJ is the change in enthalpy when 250 g of water vapor condenses at 100°C.
