Answer:
x = -6 and -2 are the zero(s) of the function
Step-by-step explanation:
To find the zero(s) of the function f(x).
Given the function:
[tex]f(x) = x^2+8x+12[/tex]
Set f(x) = 0
then;
[tex]x^2+8x+12 = 0[/tex]
Now factorize the equation as:
[tex]x^2+6x+2x+12 = 0[/tex]
⇒[tex]x(x+6)+2(x+6) = 0[/tex]
take (x+6) common we have;
[tex](x+6)(x+2)=0[/tex]
By zero product property we have;
⇒x+6 = 0 or x+2 = 0
⇒x = -6 or x = -2
therefore, the zero(s) of the function are -6 and -2
