A semicircle is attached to the side of a rectangle as shown.

What is the best approximation for the area of this figure?

Use 3.14 to approximate pi.

Select from the drop-down menu to correctly complete the statement.

A semicircle is attached to the side of a rectangle as shown What is the best approximation for the area of this figure Use 314 to approximate pi Select from th class=

Respuesta :

Area of Rectangle = 12 m
------------------------------------
a- πr^2
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d- 3 m
r- 1.5 m
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a-πr^2
a-1.5^2 π
a- 3πm^2 <-- exact answer
a- 3(3.14)
a- .42 <-- approximate answer

Answer:

[tex]15.5\ m^{2}[/tex]

Step-by-step explanation:

we know that

The area of the figure is equal to the area of a rectangle plus the area of semicircle

Step 1

Find the area of the rectangle

The area of the rectangle is equal to

[tex]A=bh[/tex]

we have

[tex]b=6\ m[/tex]

[tex]h=2\ m[/tex]

substitute

[tex]A=6*2=12\ m^{2}[/tex]

Step 2

Find the area of semicircle

The area of semicircle is equal to

[tex]A=\frac{1}{2}\pi r^{2}[/tex]

we have

[tex]r=3/2=1.5\ m[/tex]

substitute

[tex]A=\frac{1}{2}(3.14)(1.5^{2})=3.5\ m^{2}[/tex]

Step 3

Find the area of the figure

[tex]12\ m^{2}+3.5\ m^{2}=15.5\ m^{2}[/tex]