This is a test, so I'm not going to mention much. First, draw a diagram to help explain the situation. I drew a triangle with the top angle being 30 degrees, and the two legs beside it being 11 in length. Geometrically, this follows the SAS layout. You can assume that since both side legs are of equal length, their opposite/respective angles are of equal measurement. Since a triangle has 180 degree, subtract 30 (150), and then divide by two (75). So You have two 75-degree angles and a 30-degree angle.
You're looking for the bottom leg of the triangle and can use the Law of Sines to figure out the length.
[tex] \frac{11}{sin(75)} = \frac{x}{sin(30)} [/tex]
Solve for x.
