Respuesta :
The answer is x(x-8)(x+8)
Here is the process;
x^3-64x
x(x^2-64)
You know that it will be a x- and a x+ becuase there is no middle x value
x(x-)(x+)
x(x-8)(x+8)
Here is the process;
x^3-64x
x(x^2-64)
You know that it will be a x- and a x+ becuase there is no middle x value
x(x-)(x+)
x(x-8)(x+8)
remember difference of 2 perfect squares
a²-b²=(a-b)(a+b)
first factor out x
x(x²-64)
x(x²-8²)
x(x-8)(x+8)
answer is 3rd option
a²-b²=(a-b)(a+b)
first factor out x
x(x²-64)
x(x²-8²)
x(x-8)(x+8)
answer is 3rd option