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It can be noted from the given that a = 1, b = -8 and c = -9. To transpose c to the other side of the equation, all that needs to be done is to add 9 to both sides of the equation,
                        x² - 8x -9 + 9 = 0 + 9 
The answer would be,
                        x² - 8x = 9
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By using Bhaskara's formula we will see that the solutions are x = 9 and x = -1

How to solve a quadratic equation?

Remember that for a quadratic equation of the form:

x^2 + b*x + c = 0

The solutions are given by Bhasakara's formula:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2*a}[/tex]

In this case, we want to write:

x^2 + b*x = c

Then we want to replace c by -c in the formula.

So we start with:

x^2 - 8x - 9 = 0

We add 9 in both sides:

x^2 - 8x = 9.

Now using Bhaskara's formula we get:

[tex]x = \frac{8 \pm \sqrt{(-8)^2 - 4*1*(-9)} }{2*1} \\\\x = \frac{8 \pm 10 }{2}[/tex]

Then the two solutions are:

  • x = (8 + 10)/2 = 9
  • x = (8 - 10)/2 = -1

If you want to learn more about quadratic equations, you can read:

https://brainly.com/question/1214333

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