jasminekalani
contestada

A rectangle’s length is 5 inches more than twice its width. Its area is 50 square inches. Which equation can be used to find its width, w? 2w(2w + 5) = 50 2w(w + 5) = 50 w(2w + 5) = 50 w(w + 5) = 50

Respuesta :

carlosego

For this case we define the following variables:

  • L: length of the rectangle
  • w: width of the rectangle

We have that by definition, the area of a rectangle is given by:

[tex]A = w * L[/tex]

Then, we have that the length is 5 inches more than twice its width:

[tex]L = 2w + 5[/tex]

Substituting values we have:

[tex]w (2w + 5) = 50[/tex]

Answer:

An equation that can be used to find its width, w is:

[tex]w (2w + 5) = 50[/tex]

The equation that can be used to find the width of the rectangle is [tex]50 =(5+2W)\times W[/tex].

Given to us

  • A rectangle’s length is 5 inches more than twice its width.
  • The area of the rectangle is 50 inches².

We will use 'L' to represent the length of the rectangle, while 'W' to represent the Width of the rectangle.

Length of the Rectangle

length is 5 inches more than twice its width, therefore,

[tex]L = 5+ 2W[/tex]

Area of the rectangle

The area of the rectangle is 50 square inches,

[tex]\rm{Area = Length \times Width}[/tex]

Substituting the values,

[tex]50 =L\times W[/tex]

Substituting the value of L,

[tex]50 =(5+2W)\times W[/tex]

Hence, the equation that can be used to find the width of the rectangle is [tex]50 =(5+2W)\times W[/tex].

Learn more about Area of Rectangle:

https://brainly.com/question/14383947

Otras preguntas