The math club and the science club had fundraisers to buy supplies for a hospice. The math club spent $135 buying six cases of juice and one case of bottled water. The science club spent $110 buying four cases of juice and two cases of bottled water. How much did a case of juice cost ? How much did a case of bottled water cost ?

Respuesta :

juice=20$ a case. water=15$ a case

The cost of each case of juice is $20 and the cost of each bottled water is $15.

What is the cost of a product?

The cost of a product is the price to purchase it.

Let, the cost of each case of juice and each bottled water is x and y respectively.

Given, the math club spent $135 buying six cases of juice and one case of bottled water.

Therefore, 6x + y = $135 -----(1)

The science club spent $110 buying four cases of juice and two cases of bottled water.

Therefore, 4x + 2y = $110 -----(2)

From equation (1), we get:

⇒ y = ($135 - 6x)

Putting the value of 'y' in equation (2), we get:

4x + 2($135 - 6x) = $110

⇒ 4x + $270 - 12x = $110

⇒-8x = $(110 - 270)

⇒ -8x = - $160

⇒ x = $20

Putting the values of 'x' in equation (1), we get:

y = ($135 - 6x) = ($135 - 6 × $20) = ($135 - $120) = $15

Therefore, cost of each case of juice is $20 and the cost of each bottled water is $15.

Learn more about the cost of a product here: https://brainly.com/question/16677716

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