Respuesta :
joules =mass over a distance
11N*0.3m=3.3 Joules
efficiency= energy out/energy in *100%
energy out =energy of the tool=3 J
Energy in = added energy (man)=3.3 J
3/3.3*100%=90.91%
11N*0.3m=3.3 Joules
efficiency= energy out/energy in *100%
energy out =energy of the tool=3 J
Energy in = added energy (man)=3.3 J
3/3.3*100%=90.91%
Answer : The efficiency of the screwdriver is [tex]90.91\%[/tex]
Explanation :
Applied force on the handle of screwdriver, F = 11 N
Distance covered by the input force, d = 0.3 m
Output work, [tex]W_o=3\ J[/tex]
Efficiency of the screwdriver is given by the following relation :
[tex]E=\dfrac{W_o}{W_i}\times 100[/tex]
[tex]E=\dfrac{3\ J}{11\ N\times 0.3\ m}\times 100[/tex]
[tex]E=90.91\%[/tex]
Hence, this is the required solution.