firsly, the speed of Yochanan is not constant. So he has done a motion that contains an acceleration c.
for this type of movment, the equation is X= 1/2ct²+Vit
and with this last, we can find the equation of speed by dX/dt= ct + Vi
so v= ct+Vi
Vi the initial speed
n average speed of 60 km/h until he got to school implies 60=ct+ 5,
t =1.5 hour, so c= 60 - 5 / 1.5 = 56.66
and by using the formula during the motion with the bus)
V²f - V²i = 2. c (xf -xi) so V²f= 3600km/h V²i = 25 km/h
we can find xf -xi= V²f - V²i / 2c, and xf -xi= 31.54 km
but the total distance is 35 km,
so 35km - 31.54km = 3.45 km
yochanan coverd 3.45 kmby walking
yochanan coverd 31.54 km km by riding bus
