Respuesta :
Momentum P is conserved because there are no external forces acting on the system.
P before = P after = m₁ v₁ + m₂ v₂
m₁ = 1
m₂ = 5
before:
v₁ = 1
v₂ = 0
Pᵇ = 1·1 + 5 · 0
after:
v₁ = v₂
Pᵃ = Pᵇ
P before = P after = m₁ v₁ + m₂ v₂
m₁ = 1
m₂ = 5
before:
v₁ = 1
v₂ = 0
Pᵇ = 1·1 + 5 · 0
after:
v₁ = v₂
Pᵃ = Pᵇ
Answer:
B) 1 kg m/s.
Explanation:
A 1-kg chunk of putty moving at 1 m/s collides with and sticks to a 5-kg bowling ball initially at rest. The bowling ball and putty then move with a momentum of
A) 0 kg m/s.
B) 1 kg m/s.
C) 2 kg m/s.
D) 5 kg m/s.
E) more than 5 kg m/s.
From the principle of momentum which states that, in a system of colliding bodies, the total momentum before collision must be equal to the total momentum after collision.
m1u1+m2u2=(m1+m2)V
since the collision is inelastic
1*1+5*0=momentum after collision
1kgm/s =momentum after the impact