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Suppose C⃗ =A⃗ +B⃗ where vector A⃗ has components Ax = 5, Ay = 2 and vector B⃗ has components Bx = -3, By = -5. What is the direction of vector C⃗ ?

Respuesta :

First, find the components of vector C (I don't know how you added the vector arrow but that's pretty cool).

Ax + Bx = Cx, Ay + By = Cy
5 + -3 = 2, 2 + -5 = -3

Vector C can be represented as 2x, -3y.

Next, using a trigonometric function tangent you may find the angle from the origin

[tex] \theta [/tex] = arctan(-3/2)

[tex] \theta = -56.31[/tex]° [tex]= -0.983[/tex]rad

Answer:

326,3° or 146,31°

Explanation:

So you know that A=(5,2) and B=(-3,-5)

so C is going to be=(5,2)+(-3,-5)=(2,-3)

The direction of a vector is the measure of the angle it makes with a horizontal line.  One of the following formulas can be used to find the direction of a vector:

tanα=[tex]\frac{x}{y}[/tex]

tanα=[tex]\frac{2}{-3}[/tex]---> arctg([tex]\frac{2}{-3}[/tex])=α=326,3° or 146,31°