Respuesta :
First, find the components of vector C (I don't know how you added the vector arrow but that's pretty cool).
Ax + Bx = Cx, Ay + By = Cy
5 + -3 = 2, 2 + -5 = -3
Vector C can be represented as 2x, -3y.
Next, using a trigonometric function tangent you may find the angle from the origin
[tex] \theta [/tex] = arctan(-3/2)
[tex] \theta = -56.31[/tex]° [tex]= -0.983[/tex]rad
Ax + Bx = Cx, Ay + By = Cy
5 + -3 = 2, 2 + -5 = -3
Vector C can be represented as 2x, -3y.
Next, using a trigonometric function tangent you may find the angle from the origin
[tex] \theta [/tex] = arctan(-3/2)
[tex] \theta = -56.31[/tex]° [tex]= -0.983[/tex]rad
Answer:
326,3° or 146,31°
Explanation:
So you know that A=(5,2) and B=(-3,-5)
so C is going to be=(5,2)+(-3,-5)=(2,-3)
The direction of a vector is the measure of the angle it makes with a horizontal line. One of the following formulas can be used to find the direction of a vector:
tanα=[tex]\frac{x}{y}[/tex]
tanα=[tex]\frac{2}{-3}[/tex]---> arctg([tex]\frac{2}{-3}[/tex])=α=326,3° or 146,31°