Respuesta :

fg = 15

2/5(25) = 10
25-10 = 15

Answer:  The required length of FG is 15 units.

Step-by-step explanation:  Given that the length of the segment EG is 25 units and the point F is [tex]\dfrac{2}{5}[/tex] of the way between E and G.

We are to find the length of FG.

The given information is shown in the attached figure below.

Since the point F is  [tex]\dfrac{2}{5}[/tex] of the way between E and G, so we must have

[tex]EF=\dfrac{2}{5}\times EG\\\\\\\Rightarrow EF=\dfrac{2}{5}\times25\\\\\Rightarrow EF=10.[/tex]

Therefore, the length of FG is given by

[tex]FG=EG-EF=25-10=15.[/tex]

Thus, the required length of FG is 15 units.

Ver imagen ColinJacobus