The volume of 88 grams of CO2 gas at STP is 44.8 litres
Given that 1 mole of CO₂ at STP has a volume of 22.4 liters. This can be written as:
1 moles CO₂ at STP = 22.4 litres ....................... 1
We need to get the volume of 88 grams of CO₂ at STP.
We need to get the mole of 88 grams of CO₂
molar mass of CO₂ = 12 + (2*16)
molar mass of CO₂ = 12 + 32
molar mass of CO₂ =44g/mol
mole of 88 grams of CO₂ = 88/44 = 2 moles
2 moles of CO₂ = x .................................. 2
Divide equation 1 and 2 to have;
[tex]\frac{1}{2} = \frac{22.4}{x} \\x = 2 \times 22.4\\x = 44.8 litres\\[/tex]
Hence the volume of 88 grams of CO2 gas at STP is 44.8 litres
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