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A tank contains a gas mixture of 0.852 atm of He, 685 mmHg of O2, and 455 mmHg of N2. What is the pressure in mmHg of the gas mixture?

Respuesta :

taskmasters
the pressure of the gas mixture is just equal to the sum of the partial pressure of each gas present in the tank
total pressure = P_he + P_O2 + P_N2
total pressure = 0.852 mm Hg + 685 mm hg + 455 mm hg
total pressure = 1140.852 mm hg
sebassandin

Answer:

P=1787.52mmHg

Explanation:

Hello,

By using the Dalton's law of partial pressure, one computes the total pressure including the proper units conversion as shown below:

[tex]P=P_{He}+P_{O_2}+P_{N_2}\\P=0.852atm*\frac{760mmHg}{1atm} +685mmHg+455mmHg\\P=1787.52mmHg[/tex]

Best regards.

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