Your final answer is 2y(3x + 2)(4x + 3)
First, you do what you do with single brackets and find a common factor. In this case, all terms are divisible by 2y, so you take that out and put it outside the bracket:
2y(12x^2 + 17x + 6)
Now you can factor again, but this time you're factoring the inside of the brackets because it is a quadratic expression. Factoring will be difficult, as neither the end number or the number attached to the x^2 is a prime, but I will try to show you:
12x^2 + 17x + 6
Factors of 6: 1, 6, 2, 3
Now we need to find a pair that adds up to 17 when both of the numbers are multiplied by factors of 12, which are 1, 12, 2, 6, 3, 4. This would look too long, so I'm just going to tell you that it's (3 × 3) + (4 × 2) = 9 + 8 = 17
You can now factorise the entire expression into 2y(3x + 2)(4x + 3)
I hope this helps! I know it looks really long so let me know if I lost you anywhere :)
