Answer:
BC = 143
JC = 10
Step-by-step explanation:
Similar triangles:
In similar triangles, the corresponding sides are in same ratio.
ΔABC ~ ΔAGH
[tex]\sf \dfrac{BC}{GH} = \dfrac{AB}{AG}\\\\\\\dfrac{BC}{22}=\dfrac{130}{20}\\\\[/tex]
[tex]\sf BC =\dfrac{130}{20}*22[/tex]
= 13 * 11
[tex]\sf \boxed{BC = 143}[/tex]
11) ΔJLK ~ ΔJBC
[tex]\sf \dfrac{JC}{JK} = \dfrac{JB}{JL}\\\\\\\dfrac{JC}{40}=\dfrac{12}{48}\\\\JC = \dfrac{12}{48}*40\\\\JC = \dfrac{1}{4}*40\\\\JC = 1*10\\\\\boxed{\bf JC = 10}[/tex]
