a gas mixture containing no2, co2 and so2 occupies 50.0 l at 1.75 atm and 325 k. if there are 37.7 g of no2 in the mixture, what is the mole fraction of no2 and the partial pressure of no2 in this mixture?

Respuesta :

the mole fraction of no2 and the partial pressure of no2 in this mixture is 0.438 atm

Calculation :

let n be the total number of mole of gas mixture

use,

P*V = n*R*T

1.75*50.0 = n*0.082*325

87.5 = n*26.65

n = 3.28 mole

molar mass of NO2 = 46 g/mol

number of mol of NO2 = (mass of NO2)/(molar mass of NO2)

= 37.7/46

= 0.82 mole

mole fraction of NO2 = (number of mol of NO2)/n

= 0.82/3.28

= 0.25

pNO2 = (mole fraction of NO2)*(total pressure)

= 0.25*1.75

= 0.438 atm

The force applied perpendicular to the surface of an object per unit area over which that force is distributed.

Pressure is standard machine size. Various units are used to express pressure. Some of these are units of force divided by units of area. For example, the SI unit of pressure, Pascal (Pa), is 1 Newton per square meter (N/m2). Similarly, pound-force per square inch (psi) is the traditional unit of pressure in imperial and US systems. Pressure can also be expressed as standard atmospheric pressure.

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