Respuesta :
There is 50% chance of carrying the mutation, so there is a 50% chance that IV-1 will show the disease.
The glucose-6-phosphate dehydrogenase alleles allow one to trace an individual's X chromosomes throughout the pedigree, and determine the probability that an individual inherits the beneficial X allele that causes there is a disease.
Examining person III-3, who has the disease, one can conclude that the "A" polymorphic form of glucose-6-phosphate dehydrogenase goes with the disease locus. III-1 inherited his "A" allele from his mother (II-1), who has two "A" alleles, one on each X chromosome. Since we do not know which X chromosome in II-1 contains the mutated allele, II-1 has a 50% chance of passing on the X chromosome with the mutation to its daughter, III-1 ("B " allele in III. -1 from his father). When III-1 and III-2 have their child, IV-1, the "A" allele in IV-1 must come from the mother, because the father passed the Y chromosome to IV-1, not his X chromosome. .
This is the same chromosome that has a 50% chance of carrying the mutation, so there is a 50% chance that IV-1 will show the disease.
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