We can arrange the group in 120960 different ways.
Given,
Number of adults = 7
Number of children = 4
We have to find the number of ways they can stand when no two children are allowed to stand together;
Here,
Arrange 7 adults in a row of 7 ; 7
Number of arrangements = 7! = 5040
Consider that there are four possible placements for a child, but only one youngster can be placed in each of them: on either side of the row of adults, or in between two adults.
Consequently, pick one place for each youngster from the possibilities below: 4 for the first adult, 3 for the second,... the final adult's two options are = 4 × 3 × 2 = 24 arrangements
Add the two groupings together = 5040 × 24 = 120960
Therefore,
There is 120960 ways to arrange the standing position of the group.
Learn more about arrangement of group here;
https://brainly.com/question/18530971
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