The number of integers between 1 to 9999, that do not contain any of the digits 2, 3, 4 and 5 is 1295
The integers range = 1 to 9999
The number do not contains 2, 3, 4, 5
The remaining numbers = 0, 1, 6, 7, 8, 9
Total number of digits = 6
Here the repetition of the number are allowed
Here we have to use the permutation
Number of 4 digits numbers possible = 6^4 - 6^3
= 1080
Number of 3 digits numbers possible = 6^3 - 6^2
= 180
Number of 2 digits numbers possible = 6^2 - 6^1
= 30
Number of 1 digit numbers possible = 6^1 - 6^0
= 5
Total number possible = 1080 + 180 + 30 +5
= 1295
Therefore, there are 1295 numbers
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