given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit can be repeated in an integer?

Respuesta :

There are 12 different positive two digit integers can be formed using these digits if a digit can be repeated in an integer.

Integer:

An integer is zero (0), a positive integer (1, 2, 3, etc.), or a negative integer with a minus sign (-1, -2, -3, etc.). A negative number is the additive reciprocal of the corresponding positive number. In mathematics languages, sets of integers are often denoted by a bold Z or a bold {Z}.

Given the question :

The number of different positive two integer number can be obtained by:

P(4, 2) = 4P2

We know that:

[tex]^nP_r[/tex] = n! / (n - r)!

⁴P₂ = 4! / (4 - 2)!

⁴P₂ = 4! / 2!

⁴P₂ = (4 * 3 * 2 * 1) / ( 2 * 1)

⁴P₂ = 24 / 2

⁴P₂ = 12

Hence, 12 different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer.

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