consider the construction of a pen to enclose an area. you have 400 ft of fencing to make a pen for hogs. if you have a river on one side of your property, what are the dimensions (in ft) of the rectangular pen that maximize the area?

Respuesta :

The length and width of the rectangular pen that optimizes the area are 400 feet and 200 feet, respectively, according to the perimeter of a rectangle.

what is perimeter ?

The perimeter of a shape is the sum of the lengths of all its edges. For example, a triangle has three edges, hence its perimeter is equal to the sum of those three lengths.The perimeter of a form can be calculated by adding the lengths of all its sides. A perimeter example is what? A field with a length of 24 yards and a width of 15 yards, for instance, will have a perimeter of 78 yards.

calculation

In order to construct a hog pen, I have 800 feet of fencing.

Assume that "l" represents the rectangle's length and "w" its width.

One of your properties borders a river that I own.

I can secure my property with fencing on its three sides.

because of this, the fencing's necessary perimeter p = l + 2w

The fencing's perimeter is now equal to

⇒ l + 2w = 800

= l = 800 - 2w

now the  rectangle's area  = A = lw

Therefore,  A = l * w = w ( 800 - 2w ) = 800w - [tex]2w^{2}[/tex]

By diffusing the area equation, we can figure out the rectangle's greatest area.

Therefore, A' = 800 - 4w

Again, A" = -4

The rectangle has the largest area since the second order differentiation is constant negative.

Put simply, we obtain: A' = 0 , A' = 800- 4w

⇒800- 4w = 0

⇒ 4 w = 800

⇒ w = 200

So the rectangle has a 200-foot width.

The rectangle's length is currently:

l = 800 - 2w = 800 - 2 ( 200 ) = l = 400 feet

The length and width of the rectangular pen that optimizes the area are 400 feet and 200 feet, respectively, according to the perimeter of a rectangle.

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