Respuesta :
given data
the mass of a hoop with a radius of 1.0m is 6.0kg.
it rolls across a horizontal surface with a speed of 10.0m/s
we know that,
Total energy of the hoop=Translational Kinetic energy+ Rotational Kinetic energy=21mv2+21Iω2
For hoop, I=mr2
Also v= r ω
Thus total energy=21mv2+21mr2(r v)2=mv2
Hence the work required to stop the hoop=Its total energy=mv2=100×0.1J=1J
1JOULE work is required stop to hoop.
What is translational energy?
translational energy (plural translational energies) (physics) The energy of the molecules of a fluid due to motion (translation rather than rotation or vibration).
What is an example of translational kinetic energy?
A train moving along a railroad track, an object in free fall due to gravity, a car driving on a road, the motion of a bullet fired from a gun, or the expansion of a galaxy are examples of translational kinetic energy.
rotational energy
Rotational energy, or angular kinetic energy, is the kinetic energy due to the rotation of an object and is a fraction of its total kinetic energy.
to know more about rotational energy visit
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