xm denotes the number of the page that was added twice. By solving the equation, we can find xm = (S' - S)/2, which is the number of the page that was added twice.
Let the page numbers be denoted by x1, x2, x3, ... , xn.
The sum of the page numbers is given by S = x1 + x2 + x3 + ... + xn.
The sum of the page numbers with the page number added twice is S' = x1 + x2 + x3 + ... + xn + xm + xm
Therefore, S' = S + 2xm
Since S' = S + 2xm, then 2xm = S' - S
Therefore, xm = (S' - S)/2
Therefore, the number of the page that was added twice is xm = (S' - S)/2.
Let x1, x2, x3, ... , xn denote the page numbers of a book. The sum of the page numbers is denoted by S. When the page numbers were added, one of the page numbers was mistakenly added twice, resulting in an incorrect sum of S'. Therefore, S' = S + 2xm, where xm denotes the number of the page that was added twice. By solving the equation, we can find xm = (S' - S)/2, which is the number of the page that was added twice.
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