in a large population of adults the mean iq is 112 with a standard deviation of 20. what is the probabilty of selecting 30 adults that have an average iq score of 114.5 or more

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Answer:

Step-by-step explanation:

To solve this problem, we need to use the standard normal distribution. The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. We can use the standard normal distribution to find probabilities for any normal distribution by converting the values we are interested in into standard units.

To find the probability of selecting 30 adults that have an average IQ score of 114.5 or more, we first need to find the number of standard deviations that 114.5 is above the mean of 112. We can do this by subtracting the mean from the value we are interested in and dividing by the standard deviation:

(114.5 - 112) / 20 = 0.125

This tells us that a score of 114.5 is 0.125 standard deviations above the mean.

To find the probability of selecting 30 adults with an average IQ score of 114.5 or more, we can use a table of the standard normal distribution or a calculator to find the probability of selecting a value that is 0.125 standard deviations above the mean or more. This probability is approximately 0.8944.

Therefore, the probability of selecting 30 adults that have an average IQ score of 114.5 or more is approximately 0.8944.

To know more about standard normal distribution visit :

https://brainly.com/question/29973786

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