The face difference between the waves at point X₁=18m and X₂=19m is [tex]2\pi[/tex]
We should know that we are asked to determine the phase angle between the two waves.
The given parameters are
Wavelength 2m
Length of the waves = 18m and 19m
This can be determined thus
(Δx) change in length 19-18 = 1m
Wave length = 2m
Therefore. 1m = [tex]\frac{\pi }{2}[/tex]
or Ф = [tex]\pi[/tex] radian
This implies that ΔФ=[tex]\pi -\pi[/tex]=0
It can also be written as ΔФ=[tex]\pi +\pi[/tex]=2[tex]\pi[/tex]
In conclusion, the face difference between the waves at point X₁=18m and X₂=19m is [tex]2\pi[/tex]
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