Answer: A
Step-by-step explanation:
Before we find the equation of the perpendicular line, we have to find the slope of the original line.
The slope-intercept form of the equation is y=mx+b, so let's change that.
[tex]-2x+3y=-6[/tex] [add both sides by 2x]
[tex]3y=2x-6[/tex] [divide both sides by 3]
[tex]y=\frac{2}{3} x-2[/tex]
This gives slope as [tex]\frac{2}{3}[/tex].
There are 2 things for us to do to find the slope of a perpendicular line.
1. reciprocal
2. change sign
Let's apply those rules.
1. [tex]\frac{3}{2}[/tex]
2. [tex]-\frac{3}{2}[/tex]
Now, we can find the perpendicular lines by plugging in our new point.
[tex]y=-\frac{3}{2} x+b[/tex] [plug in x and y]
[tex]-1=-\frac{3}{2}(6)+b[/tex] [multiply]
[tex]-1=-9+b[/tex] [add both sides by 9]
[tex]b=8[/tex]
Now we can plug in for our slope-intercept equation.
[tex]y=-\frac{3}{2} x+8[/tex]
Since answers are in standard form, we have to manipulate it.
[tex]y=-\frac{3}{2} x+8[/tex] [add both sides by [tex]\frac{3}{2} x[/tex]]
[tex]\frac{3}{2}x+y=8[/tex] [multiply both sides by 2]
[tex]3x+2y=16[/tex]
Therefore, our final answer is A.
