Respuesta :
(115,123) is the population mean's 68% confidence interval when a population was sampled using a 64-person sample, with a mean value of 119 and a standard deviation of 16.
Given that,
A population was sampled using a 64-person sample, with a mean value of 119 and a standard deviation of 16.
We have to find what is the population mean's 68% confidence interval.
We know that,
For a 95% confidence interval and 63 degrees of freedom, the critical t value is 1.998.
The population mean's 95% confidence interval is as follows:
(119-1.998×16/√64,119+1.998×16/√64)
=(115,123)
Therefore, (115,123) is the population mean's 68% confidence interval when a population was sampled using a 64-person sample, with a mean value of 119 and a standard deviation of 16.
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