For given function g(x) = x^4 - 2x^3 - 3x the value of x such that g'(x) = 12 is x = 2.24
In this question, we have been given a function g(x) = x^4 - 2x^3 - 3x
We need to find the value of x such that g'(x) = 12
First we find the derivative of given function g(x) with respect to x
g'(x) = 4x³ - 6x² - 3
When g'(x) = 12
4x³ - 6x² - 3 = 12
4x³ - 6x² - 3 + 3 = 12 + 3
4x³ - 6x² - 15 = 0
After solving given polynomial we get,
x = 2.24
Therefore, the value of x is 2.24
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