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Unpolarized light with insenity S is incident on a series of polarizing sheets. The first sheet has its transmission axis oriented at 0 degrees. A second polarizer has its transmission axis oriented at 45 degrees and a third polarizer oriented with its axis at 90 degrees. Determine the fraction of light intensity exiting the third sheet and without the second sheet present.

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(a) The fraction of light intensity exiting the third sheet is S/8.

(b) The fraction of light intensity exiting the third sheet without the second sheet present is zero.

What is the intensity of light?

The intensity of light is the power of light transmitted over a given area.

When an unpolarized light is passed through a polarizer then its intensity reduced to half.

When it is passed through a second polarizer with its transmission axis, θ = 45⁰

The intensity of the light becomes;

S₁ = S₀ Cos²θ

where;

  • S₀ is the initial intensity = S/2

S₁ = (S/2) [Cos (45)]²

S₁ = (S/2)(¹/₂)

S₁ = S/4

When it is passed through third polarizer with its axis,  the fraction of light intensity exiting the third sheet becomes;

S₂ = S₁ Cos²θ

S₂ = (S/4) [Cos (45)]²

S₂ = (S/4) (¹/₂)

S₂ = S/8

Without the second sheet, the fraction of light intensity becomes;

S₂ = S₁ Cos²θ

S₂ = (0) Cos²θ

S₂ = 0

Learn more about light intensity here: https://brainly.com/question/28145811

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