The radiation pressure force on the earth is 1.15×10⁹ N.
P = I/C
where
I is the intensity
c is the speed of light
In this problem, I=1360W/m² ; substituting this value, we find the radiation pressure:
P= 1360/3×10⁸ = 4.5/10⁶ Pa
The force exerted on the Earth depends on the surface considered. Assuming that the sunlight hits half of the Earth's surface (the half illuminated by the Sun), we have to consider the area of a hemisphere, which is
A= 2πr²
A= 2π(6.37×10⁶)² = 2.55×10¹⁴ m²
And so the force exerted by the sunlight is
F= pA = 1.15×10⁹ N
What is pressure?
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